Monday, 16th August, 2,004.
Correct Virgo, in brief.
The riddle is: Why are distant galactic clusters half Virgo’s size?! They aren’t. If you halve H.L. (To get the correct general distances per Hubble’s Law. dividing by four.)you halve their distances, making them half their original size. Thus they become a quarter of Virgo’s size!!
So why is Virgo Cluster’s size FOUR times that of the distant clusters?
The answer is a bit complex.
Virgo Cluster’s size is 4x that of distant clusters.(When H.L. correction applied to the distant clusters(instead of the mere 2x before).)
But distant clusters are 4x over-stated. Via Hubble’s Law needing division by 2,again, and RELATIVELY to the mags the fact that H.L. measures cover a full circumference against the magnitudinal half(once x1.57 applied(which cancels out the 1.57x later put on mags!!)!!)Thus 1C to C/2(C is Circumference.), which is the second 2:1 reduction, applies. (Thus all told need a division by four.) This cancels out Virgo’s apparent 4x too big size!! And, therefore makes it right. Agreeing with distant clusters!!!!
What I call a Double Reverse.
Where the puzzle gets twice as bad. BEFORE it gets 4 times better against 4 times worse!! Making it right.
Let me explain:-
All fields are 4d disks. Round so far as we mere 3d creatures are concerned!! However, magnitudes’ light,etc. em(electro-magnetic) radiation is received as waves STRAIGHT ACROSS S-T(THROUGH VIBRATION), to us. Thus we are only seeing half(when divided by circumferential pi/2) the distance magnitudinally as we measure AROUND by Hubble’s Law!!
This means that H.L. wise we are MEASURING circumferentially right around the circumference(which is correct per arcs), when mags wise we only go half way!! That is a 2:1(But this gets INTERNALLY cancelled out of the full picture.(Via my correction adjustments.)) (However, it affects this internal calculation!!)
Thus distant galaxies(measured by Hubble’s Law) are being read 4x what they should be. On the other hand, Virgo’s centre’s distance is RELATIVELY (To the distant clusters.)calculated (but mag wise)( AND via THE CONVERSE of H.L.) at 4x what it should be!! This now quarters(because that much closer, and therefore smaller) Virgo’s size IN RELATION TO THAT of the distant clusters. Thus removing the mysterious original double size(that of distant galactic clusters)(Which later became 4x)!!!!(RELATIVELY the distant clusters were 4x too high, whilst the Virgo Cluster was 4x too low!!)(Removing both 4x(RELATIVELY one four times up, the other four times down.), leaves them equal in size!!)(Once the 1.57x required to convert chords into arcs is applied.)(It is only RELATIVE you see!)
We now bring in the fact that mags are only HALF “vels” via seeing chord wise(Maximum is diameter from us to Far Point, which in Hubble Law terms is only HALF WAY AROUND of course!! In circumferential arc terms. Because beyond Far Point(Far end of diameter.), we are getting nearer home again!!!!)
Virgo Cluster is H.L. Baseline. Zero in H.L. terms. Doubling zero is still zero!! So even if you say Virgo is H.L. obtained too, doubling it still leaves it at zero. Distant Clusters remain halved in size.(Referring to the second halving.) Virgo Cluster does not change!!!!
I realize that this is strange and complex, but it is the answer!!!!
In a nut-shell:-(Two kinds of distance, remember: 1. AROUND the arcs, via Hubble’s Law.) 2. ACROSS the arcs, by CHORDS, MAGNITUDINALLY!!!!)
When the Hubble Law correction of divide by two is applied, this makes the galactic clusters halve their distances. And halve their sizes. So now 4x smaller than Virgo!!(Against the formerly 2x smaller.)
On the other hand, THOUGH Virgo’s(centre’s) distance needs the 1.57x applying(to convert chord into arc!!). The fact that correct Mv not removed. Nor CORRECT OM removed(Obscuring Matter.)!! Making Virgo’s centre (via averages!!) a good 4x closer, no problem(Despite the x 1.57!!)!! Thus reducing its size four fold. That now equalizes sizes. By cancelling out 4x smaller size of distant galactic clusters!!!!
Distant galactic clusters 4x over-stated per distances.(Obtained by using Hubble’s Law.)
Once(x2) on account of Hubble’s Law needing dividing by two, and once on account of arc distances being measured right around circumference(another x2). Making x4 all together!! Thus galactic clusters’ sizes are 4x Virgo(to this point)!
On the other hand, but RELATIVELY, Virgo’s centre’s distance is measured MAGS. (chord) wise! NOT H.L!!(So divide by 2 against arcs of distant galaxies via Hubble’s Law.) And another division by 2 on account of the fact that mags measure only HALF way out!!(Maximum chord is diameter from observer to far point!!)(Allow for pi/2(1.57) factor, of course. Which also cancels out RELATIVELY!!) Thus 4x too close to us! The two 4x cancel out BECAUSE they are relative!! One is too high as much as the other is too low!!!! Sizes cancel out, by following suit!!(Distant galactic clusters and Virgo Cluster are now the same size!!!!)
Virgo Cluster(centre thereof) is measured mags chords’ wise.
Which is only half that with Hubble Law’s arc method with the distant galactic clusters!!(As arcs go right around circ, while mags go up to half way(Diameter from observer to Far Point)!! Pi/2 (1.57 factor) allowed. Of course!!) So simple!!!!
Now go to A706 for the final and simplest expostion of The Virgo Solution!!!!!